Variations:
We say that
x is directly proportional to
y, if
x =
ky for some constant
k and we write,
x
y.
We say that
x is inversely proportional to
y, if
xy = k for some constant
k and
we write, x  | 1 | . |
y |
***
The concepts of ratios, proportions and variations, which build upon
each other, all involve change. Ratios are used to compare two
quantities. Proportions are merely statements of equality involving
ratios and variations involve problems written as proportions.
Ratios
While you may not realize it, you use ratios every day. For example,
when you talk about a vehicle’s rate of travel being 45 mph, you are
talking about the ratio of distance traveled to time traveled. Ratios
are used to compare two quantities. They are typically written in one of
two ways: as a fraction or with a colon (:). The ratio read as “4 to
10” could be written as 4/10 or as 4 : 10. The ratio expressing the
relationship between a day and a week could be written as 1/7 or 1 : 7
because there are 7 days in a week.
Keep in mind, when you write a ratio as a fraction, it is not a fraction in the true sense of the term (i.e. part over whole).
Proportions
A proportion is a mathematical statement equating two ratios. Two
ratios are said to be equal if, when written in fractional form, the
fractions are equivalent fractions. You can compare and solve ratios
using cross multiplications. If the cross products are equal, the ratios
are equal.
When solving a proportion question, you’ll want to rewrite the proportion in fractional format. Let’s take a look at an example:

Note, in the above example, you could have also solved this problem
by observation if you recognized that 4/12 is simply 1/3. One-third of 6
is 2. Observations such as this will provide significant time savings
on the exam, but on more difficult problems, it’s important to know the
basics.
Variations
Variations deal with explaining, in mathematical language, how one
quantity changes with respect to one or more other quantities. There are
two primary types of variation: direct variation and inverse variation.
We’ll look at these first, and then take a look at two extensions of
these concepts: joint variation and combined variation.
Direct Variation
Let’s take a look at an example of direct variation. The amount of
flour needed in a bread recipe varies with the number of loaves being
made. Making more loaves will require more flour; making fewer loaves
will require less flour. In direct variation, the variables (amount of
flour and number of loaves in our example) will move in the same
direction.
Problems involving direct variation can be solved using proportions. Let’s see this in action:
If it takes 3 gallons of paint to cover 100 square feet, how many gallons of paint will be needed to cover 600 square feet?
The problem gives us the ratio of 3 gallons of paint to cover 100
square feet. We can use this information to set up our proportion:
Cross-multiply and solve for x:
When we say "y varies directly as x," we could also write:
In the above equation, k is called the constant of
variation. In the paint example, the number of gallons of paint varies
directly with the square footage that will be covered. The constant of
variation is 3/100. You would then have:
Inverse Variation
When two variables or quantities change in opposite directions, you
have inverse variation. Let’s take a look at an example: The time it
takes to paint a house varies with the number of people doing the work.
In this example, the time required to paint the house varies
inversely with the number of people painting. This means the more people
painting the house, the less total time it will take to paint. When we
say "y varies inversely with x," we can express this as:
Once again, k is the constant of variation. We can find k by rearranging the formula as k = xy. Thus, k is simply the product of the known values for the two variables. Let’s consider the following example:
A particular hotel has a custodial staff of 12 employees, and they
can typically clean all of the hotel rooms in 6 hours. If four members
of the custodial staff are not at work today, how long will it take the
remaining custodians to clean all of the hotel rooms?
In this example, the total time taken to complete the job is
inversely proportional to the number of workers. The constant of
variation, k, is simply 6 • 12 = 72. We want to know the
numbers of hours it will take the remaining custodians to do the job.
Since 4 are absent, that leaves 8 workers (12 – 4 = 8).
We can thus solve the problem as detailed below:
The correct answer is 9 hours.
Joint Variation
Joint variation is just an extension of direct variation. When we say that "y varies jointly with x and z" we have an example of joint variation. This can be written as:
Again, k is the constant of variation, simply the ratio of y to x and z (x times z) Here’s an example:
The variable y varies jointly with x and z. The value of y is 12 when x is 4 and z is 8. What is y when x = 6 and z = 10?
Since it is pretty clear we have a joint variation problem, we solve for k by plugging the known variables (y = 12 when x is 4 and z is 8) into our joint variation equation:
Once we have a value forwe plug this back into the equation of joint
variation along with the variables we do know and solve for our unknown:
Combined Variation
Combined variation involves both direct and inverse variation. For example, if we say "y varies directly with x and inversely with z," we are faced with combined variation. This can be written as follows:
Consider the following example:
It takes 2 hours for 3 people to paint 100 ft. of 6-ft. fencing.
Assuming that each person is capable of painting at the same rate, how
long will it take for 12 people to paint 1,800 ft. of the same fencing?
The total time (t) needed to paint a section of fencing is directly proportional to the length of the fence (l) and inversely proportional to the number of people (n) who are painting. (Note, we are using different letters for our variables, but it doesn’t matter!).
The steps are the same as in the other example problems. First, we determine the constant of variation, k.
Now that we have k, we plug it into the equation and solve for the missing variable:
The correct answer is 9 hours.
Examples
- There are 14 boys and 16 girls in Tyler’s class. What ratio best
represents the relationship between the number of boys and the number
of students in Tyler’s class?

- If the ratio of A to B is 3 : 4, and the ratio of B to C is 2 : 3, what is the value of A when C is 5?

Answers and Explanations
- The correct answer is C. It’s critical to read
this question carefully as it’s easy to make a careless error on this
one. The question gives you the number of boys (14) and the number of
girls (16), but it’s asking you for the ratio between the number of boys
(14) and the total number of students (14 + 16 = 30). Sneaky. The ratio
itself could be written as a fractional format (14/30) or as 14 : 30.
None of these are choices however, so you need to reduce to find the
answer, choice C, which could have just as easily been written as 7 :
15. You’ll note that the choices also include options for the ratio of
boys to girls (choices A and D), and the ratio of girls to the total
(choice E). It’s not a tough question conceptually, but it’s an easy one
to miss if you aren’t paying close enough attention!
- The correct answer is C. You are given two
separate ratios with one common variable (B). You’ll need to combine
them. If the ratio of A to B is 3 : 4 and B to C is 2 : 3, the common
variable needs to be the same in both relationships to combine. If you
multiply both B and C by 2 in the second relationship, it’s not actually
changing -- 2 : 3 is the same as 4 : 6 -- but now you can combine the
two relationships to have a ratio A to B to C of 3 : 4 : 6. Remove B and
you have your ratio of A to C, or 3 : 6. To determine what A would be
if C were 5, set it up as a proportion and cross multiply: 32/6 = x/5. Solve for the missing value, 3 • 5 = 6 • x, so 15 = 6x, and thus, x = 15/6 = 5/2.
*********
Practice
https://www.mycollegeoptions.org/Core/Content.MyCollegeOptions.org/media/MyCollegeOptionsMedia/TestPrep/Math_Ratios_Practice.pdf
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