TDS QUIZ

1.Busses start from a bus terminal with a speed of 20 km/hr at
intervals of 10 minutes. What is the speed of a man coming from the
opposite direction towards the bus terminal if he meets the buses at
intervals of 8 minutes?
a.3 km/hr
b.4 km/hr
c.5 km/hr
d.7 km/hr
e.None of these

2.The distance between two cities A and B is 330km. A train starts
from A at 8 (a)m. and travels towards B at 60 km/hr. Another train
starts from B at 9 (a)m. and travels towards A at 75 km/hr. At what
time do they meet?
a.10 am.
b.10 : 30 am.
c.11 am.
d.11 : 30 am.
e.None of these

3.Two trains are moving on two parallel tracks but in opposite
directions. A person sitting in the train moving at the speed of 80
km/hr passes the second train in 18 seconds. If the length of the
second train is 1000 m, its speed is?
a.100 km/hr
b.120 km/hr
c.140 km/hr
d.150 km/hr
e.None of these

4.In covering a distance of 30 km, Abhay takes 2 hours more than
Sameer. If Abhay doubles his speed, then he would take 1 hour less
than Sameer. Abhay's speed is?
a.5 kmph
b.6 kmph
c.6.25 kmph
d.7.5 kmph
e.None of these

5.It takes eight hours for a 600 km journey, if 120 km is done by
train and the rest by car. It takes 20 minutes more, if 200 km is done
by train and the rest by car. The ratio of the speed of the train to
that of the cars is?
a. 2 : 3
b. 3: 2
c. 3 : 4
d. 4 : 3
e. None of these

Answers with Explanation:-

1.(c)
Distance covered in 10 minutes at 20 kmph = distance covered in 8
minutes at (20+x) kmph
20× 10/60=8/60(20+x)
200 = 160 + 8x
8x = 40
x=40/8=5 kmph

2.(c) Distance travelled by first train in one hour
= 60 x 1 = 60 km
Therefore, distance between two train at 9 a.m.
= 330 – 60 = 270 km
Now, Relative speed of two trains = 60 + 75 = 135 km/hr
Time of meeting of two trains =270/135=2 hrs.
Therefore, both the trains will meet at 9 + 2 = 11 A.M.

3.(b) Let the speed of second train be x m/s.
80 km/h = (80×5)/18 m/s
According to the question 1000/(x+(80×5)/18)=18
100 – 18x + 400
x=666/18 m/s
= 600/18×18/5 km/h = 120 km/h

4.(a)
Let Abhay's speed be x km/hr.
Then, 30/x-30/2x= 3
6x = 30
x = 5 km/hr.

5.(c)
Let the speed of the train be x km/hr and that of the car be y km/hr.
Then, 120/x+480/y= 8 1/x+4/y=1/15 ....(i)
And, 200/x+400/y=25/3 1/x+2/y=1/24 ....(ii)
Solving (i) and (ii), we get: x = 60 and y = 80.
Ratio of speeds = 60 : 80 = 3 : 4.


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