Saturday 13 June 2015

Ratio Tricks

Here are some very important ratio and proportion problems shortcuts
If a number x is divided in the ratio a:b ,then
1st part will be=ax/(a+b)
2nd part will be= bx/(a+b)

Or if the number x is divided in three ratios as a:b:c , then
1st part will be=ax/(a+b+c)
2nd part will be=bx/(a+b+c)
3rd part will be= cx/(a+b+c)

The ratio of milk to water in a mixture is A:B . if P liters of water is added to the mixture, then milk to water mixture ratio becomes A:C ,
then the quantity of milk in the mixture is
=AP/(C-B)           liters
And the quantity of water in the mixture is
= BP/(C-B)           liters

If a number x is added to a ratio a:b so that the ratio becomes c:d ,
Then   x= (ad-bc)/(c-d)

If there are two numbers whose sum and difference is a and b respectively,
 then the ratio of those numbers will be = (a+b)/(a-b)

if two quantities A and B are in the ratio a:b ,
then
(A+B):(A-B)::(a+b):(a-b)

If two numbers are given in the ratio a:b and P in both numbers, the ratio becomes c:d ,
Then
1st number = aP(c-d)/(ad-bc)
2nd number = bP(c-d)/(ad-bc)
Sum of numbers = [P(a+b)(c-d)]/(ad-bc)
Difference of numbers = [P(a-b)(c-d)]/(ad-bc)

If the ratio of incomes of two persons is a:b , and also ratio of their expenses is c:d , and each person saves a sum of x rupees,
Then
Income of 1st person  = ax(d-c)/(ad-bc)
Income of 2nd person = bx(d-c)/(ad-bc)

Example:
In a mixture of milk and water, ratio of milk to water is 5:1 . if 5 liters of water is added to the mixture, the ratio becomes 5:2. Determine the quantity of milk in mixture initially?
Solution:
So in the given question, A=5, B=1, C=2, P=5
Now putting the formula as given above
Quantity of milk = AP/(C-B) = (5*5)/(2-1) = 25 liters
So the answer is
25 liters of milk is there in the initial mixture of milk and water.


Read more: http://www.meriview.in/2013/10/shortcuts-for-ratio-and-proportions.html#ixzz3cyPchFlR

2 comments:

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